Zhao Jianbo

2023/2024 2022/2023 2021/2022 2020/2021 2019/2020 2018/2019 2017/2018 2016/2017 2015/2016 2014/2015 2013/2014 2012/2013 2011/2012 2010/2011 2009/2010 2008/2009 2007/2008 2006/2007 2005/2006 2004/2005 2003/2004 2002/2003 2001/2002 2000/2001 All available

 

Nationality:  (China); Male; Born: 27 Aug 2003 (19 years)
Status: Amateur; First season as pro: 2020; Last season as pro: 2021;

Other sources: CueTracker ; World Snooker

German Masters (1-5 Feb 2023)
Rd 4 (9)		Jimmy Robertson [24]		v			Zhao Jianbo (a)		Wed 1 Feb 15:00
Q Tour 5 (9-11 Dec 2022)
Rd 1 (5)		Zhao Jianbo (a)		v			To be decided		Est. Sat 10 Dec 12:30
Q Tour 4 (25-27 Nov 2022)
Rd 1		Scott Bell (a) [61]	w/o				Zhao Jianbo (a) [21]
German Masters Qual (21-26 Nov 2022)
Q Rd 3		Zhao Jianbo (a)	5	-	0		Mark Allen [9]
Q Rd 2		Zhao Jianbo (a)	5	-	1		Ashley Hugill [106]
	Zhao replaced Liang Wenbo who has been suspended
Q Tour 3 (14-16 Oct 2022)
Rd 1		Liam Pullen (a) [40]	w/o				Zhao Jianbo (a) [16]
Scottish Open Qual (9-14 Oct 2022)
Q Rd 1		Joe Perry [29]	4	-	2		Zhao Jianbo (a)
	Zhao replaced Peter Lines.
British Open (26 Sep - 2 Oct 2022)
Rd 2		Yuan Sijun [67]	4	-	1		Zhao Jianbo (a)
Rd 1		Zhao Jianbo (a)	4	-	1		Ian Burns [84]
Q Tour 2 (16-18 Sep 2022)
Rd 3		Gao Yang (a) [16]	3	-	1		Zhao Jianbo (a) [27]
Rd 2		Zhao Jianbo (a) [27]	3	-	0		Harvey Chandler (a) [42]
Rd 1		Zhao Jianbo (a) [27]	3	-	1		Luke Pinches (a) [53]
Q Tour 1 (2-4 Sep 2022)
Rd 2		Florian Nüßle (a) [5]	3	-	1		Zhao Jianbo (a) [1]
Rd 1		Zhao Jianbo (a) [1]	3	-	1		Kayden Brierley (a) [66]
Northern Ireland Open Qual (23-28 Aug 2022)
Q Rd 2		Aaron Hill [92]	4	-	0		Zhao Jianbo (a)
	Zhao replaced Stephen Hendry who withdrew
British Open Qual (9-14 Aug 2022)
Q Rd 1		Zhao Jianbo (a)	4	-	3		Jackson Page [65]
European Masters Qual (15-24 Jul 2022)
Q Rd 1		Jimmy Robertson [25]	5	-	4		Zhao Jianbo (a)		Robertson was 4-0 down
Championship League Stage One Group 10 (1 Jul 2022)
Grp		Zhao Jianbo (a)	3	-	0		Oliver Brown [91]
Grp		Robbie Williams [54]	3	-	1		Zhao Jianbo (a)
Grp		Luca Brecel [10]	3	-	0		Zhao Jianbo (a)